Odpowiedź :
Odpowiedź:
wzór na masę:
[tex]\Huge\boxed{m=\frac{Q}{c*T} }[/tex]
Q=1,5kJ = 1500J
Obliczenia:
[tex]m=\frac{1500J}{1500\frac{J}{kg*C}*10C } \\\\\boxed{m=0,1kg}[/tex]
[tex]dane:\\\Delta T = 10^{o}C\\Q = 1,5 \ kJ = 1 \ 500 \ J\\c_{w} = 1500\frac{J}{kg\cdot^{o}C}\\szukane:\\m = ?[/tex]
Korzystamy ze wzoru na ciepło właściwe
[tex]c_{w} = \frac{Q}{m\cdot \Delta T} \ \ /\cdot(m\cdot \Delta T)\\\\c_{w}\cdot m\cdot \Delta T = Q \ \ /:(c_{w}\cdot \Delta T)\\\\m = \dfrac{Q}{c_{w}\cdot \Delta T}\\\\m = \frac{1500 \ J}{1500\frac{J}{kg\cdot^{o}C}\cdot10^{o}C}\\\\\boxed{m = 0,1 \ kg}[/tex]