[tex]\sqrt[3]{\dfrac{8}{27} } =\sqrt[3]{\dfrac{2^{3} }{3^{3} } }=\dfrac{2}{3} \\\\\\\sqrt[3]{8} =\sqrt[3]{2^{3} } =2^{3\cdot \frac{1}{3} } =2\\\\\\\sqrt[3]{2\dfrac{10}{27} } =\sqrt[3]{\dfrac{64}{27} } =\sqrt[3]{\dfrac{4^{3} }{3^{3} } }=\dfrac{4}{3} =1\dfrac{1}{3} \\\\\\\sqrt[3]{64} =\sqrt[3]{4^{3} } =4^{3\cdot \frac{1}{3} }=4\\\\\\\sqrt[3]{\dfrac{8}{27} } + \sqrt[3]{2\dfrac{10}{27} }+\sqrt[3]{64} =\dfrac{2}{3} + 1\dfrac{1}{3} + 4=6\\\\\\Nalezy~~skreslic~~liczbe~~\sqrt[3]{8}.\\Odp:~~C[/tex]
[tex]korzystam ~~ze~~wzoru:~~\sqrt[n]{x^{n} } =x^{n\cdot \frac{1}{n} } =x^{1} =x[/tex]
