Cześć!
Obliczenia
[tex]10\frac{1}{4}-8\frac{3}{4}=9\frac{4+1}{4}-8\frac{3}{4}=9\frac{5}{4}-8\frac{3}{4}=1\frac{2}{4}=1\frac{2:2}{4:2}=1\frac{1}{2}\\\\2\frac{5}{6}-1\frac{3}{8}=2\frac{5\cdot4}{6\cdot4}-1\frac{3\cdot3}{8\cdot3}=2\frac{20}{24}-1\frac{9}{24}=1\frac{11}{24}\\\\82\frac{3}{8}-1\frac{7}{12}=82\frac{3\cdot3}{8\cdot3}-1\frac{7\cdot2}{12\cdot2}=82\frac{9}{24}-1\frac{14}{24}=81\frac{24+9}{24}-1\frac{14}{24}=81\frac{33}{24}-1\frac{14}{24}=80\frac{19}{24}[/tex]
