Cześć!
a)
[tex]3\frac{4}{21}+32\frac{1}{7}=3\frac{4}{21}+32\frac{1\cdot3}{7\cdot3}=3\frac{4}{21}+32\frac{3}{21}=35\frac{7}{21}=35\frac{7:7}{21:7}=35\frac{1}{3}\\[/tex]
b)
[tex]5\frac{4}{11}+2\frac{3}{22}-1\frac{43}{44}=5\frac{4\cdot4}{11\cdot4}+2\frac{3\cdot2}{22\cdot2}-1\frac{43}{44}=5\frac{16}{44}+2\frac{6}{44}-1\frac{43}{44}=\\\\=7\frac{22}{44}-1\frac{43}{44}=6\frac{44+22}{44}-1\frac{43}{44}=6\frac{66}{44}-1\frac{43}{44}=5\frac{23}{44}[/tex]
c)
[tex]2,45-1\frac{21}{30}-(-2\frac{1}{25})=2,45-1\frac{21:3}{30:3}+2\frac{1}{25}=2,45-1\frac{7}{10}+2\frac{1\cdot4}{25\cdot4}=\\\\=2,45-1,7+2\frac{4}{100}=0,75+2,04=2,79[/tex]
d)
[tex]4\frac{1}{3}-2,(3)-3\frac{2}{7}=4\frac{1}{3}-2\frac{1}{3}-3\frac{2}{7}=2-3\frac{2}{7}=-(3\frac{2}{7}-2)=-1\frac{2}{7}\\[/tex]
