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[tex](\frac{7}{11}-0,6)+(\frac{2}{5})^2=(\frac{7}{11}-\frac{6}{10})+\frac{2^2}{5^2}=(\frac{7}{11}-\frac{6:2}{10:2})+\frac{2\cdot2}{5\cdot5}=\\\\=(\frac{7}{11}-\frac{3}{5})+\frac{4}{25}=(\frac{7\cdot5}{11\cdot5}-\frac{3\cdot11}{5\cdot11})+\frac{4}{25}=(\frac{35}{55}-\frac{33}{55})+\frac{4}{25}=\\\\=\frac{2}{55}+\frac{4}{25}=\frac{2\cdot5}{55\cdot5}+\frac{4\cdot11}{25\cdot11}=\frac{10}{275}+\frac{44}{275}=\frac{54}{275}[/tex]
