Cześć!
Od a) do d)
[tex]-2\frac{1}{4}+1\frac{1}{4}=-(2\frac{1}{4}-1\frac{1}{4})=-1\\\\-5,4+(-2,8)=-(5,4+2,8)=-8,2\\\\4,8+(-2,4)=4,8-2,4=2,4\\\\3\frac{1}{2}+(-5\frac{1}{2})=3\frac{1}{2}-5\frac{1}{2}=-(5\frac{1}{2}-3\frac{1}{2})=-2[/tex]
Od e) do h)
[tex]3,5+(-5,3)=3,5-5,3=-(5,3-3,5)=-1,8\\\\-5\frac{5}{9}+2\frac{2}{9}=-(5\frac{5}{9}-2\frac{2}{9})=-3\frac{3}{9}=-3\frac{1}{3}\\\\-6,8+(-11,3)=-(6,8+11,3)=-18,1\\\\-6\frac{3}{5}+(-2\frac{3}{5})=-(6\frac{3}{5}+2\frac{3}{5})=-8\frac{6}{5}=-9\frac{1}{5}[/tex]
Od i) do l)
[tex]7\frac{1}{3}+(-6\frac{2}{3})=7\frac{1}{3}-6\frac{2}{3}=6\frac{4}{3}-6\frac{2}{3}=\frac{2}{3}\\\\-5,11+(-3,45)=-(5,11+3,45)=-8,56\\\\-2\frac{5}{6}+(-1\frac{5}{6})=-(2\frac{5}{6}+1\frac{5}{6})=-3\frac{10}{6}=-4\frac{4}{6}=-4\frac{2}{3}\\\\4,2+(-7,8)=4,2-7,8=-(7,8-4,2)=-3,6[/tex]
