Odpowiedź:
Zad 1
P=[tex]6 {a}^{2} [/tex]
[tex]96 {cm}^{2} = 6 {a}^{2} \: \: \: \: \: | \div 6 \\ 16 {cm}^{2} = {a}^{2} \: \: \: \: \: | \sqrt{} \\a = 4cm[/tex]
przekątna sześcianu=[tex]a \sqrt{3} [/tex]
[tex]d = 4 \sqrt{3} cm[/tex]
Zad 2
[tex]6 = a \sqrt{ 3} \: \: \: \: \: | \div \sqrt{3} \\ a = \frac{6}{ \sqrt{3} } \times \frac{ \sqrt{3} }{ \sqrt{3} } \\ a = \frac{6 \sqrt{3} }{3} \\ a = 2 \sqrt{3} [/tex]
P=[tex]6\times (2 \sqrt{3} cm) ^{2} = 6 \times 4cm \times 3 cm= 72 {cm}^{2} [/tex]
V=[tex] {a}^{3} [/tex]
V=[tex](2 \sqrt{3} ) ^{3} = {2}^{3} \times \sqrt{3} ^{3} = 8 \times 3 \sqrt{3} = 24 \sqrt{3} [/tex]
V=[tex]24 \sqrt{3} {cm}^{3} [/tex]
