Cześć!
Od a) do c)
[tex]3\frac{3}{5}+\frac{6}{10}=3\frac{3}{5}+\frac{6:2}{10:2}=3\frac{3}{5}+\frac{3}{5}=3\frac{6}{5}=3+\frac{6}{5}=3+1\frac{1}{5}=4\frac{1}{5}\\\\\frac{1}{7}+5\frac{6}{21}=\frac{1\cdot3}{7\cdot3}+5\frac{6}{21}=\frac{3}{21}+5\frac{6}{21}=5\frac{9}{21}=5\frac{9:3}{21:3}=5\frac{3}{7}\\\\1\frac{5}{6}+\frac{3}{4}=1\frac{5\cdot2}{6\cdot2}+\frac{3\cdot3}{4\cdot3}=1\frac{10}{12}+\frac{9}{12}=1\frac{19}{12}=1+\frac{19}{12}=1+1\frac{7}{12}=2\frac{7}{12}[/tex]
Od d) do f)
[tex]3\frac{4}{5}+2\frac{5}{6}=3\frac{4\cdot6}{5\cdot6}+2\frac{5\cdot5}{6\cdot5}=3\frac{24}{30}+2\frac{25}{30}=5\frac{49}{30}=5+\frac{49}{30}=5+1\frac{19}{30}=6\frac{19}{30}\\\\2\frac{5}{9}+3\frac{1}{4}=2\frac{5\cdot4}{9\cdot4}+3\frac{1\cdot9}{4\cdot9}=2\frac{20}{36}+3\frac{9}{36}=5\frac{29}{36}\\\\3\frac{5}{6}+2\frac{3}{8}=3\frac{5\cdot4}{6\cdot4}+2\frac{3\cdot3}{8\cdot3}=3\frac{20}{24}+2\frac{9}{24}=5\frac{29}{24}=5+\frac{29}{24}=5+1\frac{5}{24}=6\frac{5}{24}[/tex]
