Zad 2
a) 4x - 7 = 2x + 9 |+7
4x = 2x + 16 |-2x
2x = 16 |:2
x = 8
b) 3 - 8x = 18 - 3x |+8x
3 = 18 + 5x |-18
-15 = 5x |:5
-3 = x
c) 2 - x = 12 + 7x |+7x
2 + 6x = 12 |-2
6x = 10 |:6
d) 3x + 5x - 6 = 6x + 2 |+6
8x = 6x + 8 |-6x
2x = 6 |:2
x = 3
e) 5 - 9x + 6 = 2x + 14 - x |+9x
11 = 10x + 14 |-14
-3 = 10x |:3
Zad 3
[tex]a) x(3x+2)= 3(x^{2}-4)\\3x^{2} + 2x = 3x^{2} - 12 |-3x^{2}\\2x=-12 |:2\\x=-6\\b) 6(1+2x^{2} )= 4x(1+3x)\\6+12x^{2}=4x+12x^{2} |-12x^{2}\\6=4x |:4\\\frac{6}{4} =x\\c)3x(x-5)=(3x+2)(x-1)\\3x^{2}-15x=3x^{2}-3x+2x-2 |-3x^{2}\\-15x=x-2 |+15x+2\\2=16x |:16\\\frac{2}{16}=x[/tex]
Mam nadzieję że pomogłam i liczę na naj. ♥
