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[tex]1\dfrac{3}{5}=\dfrac{1\cdot5+3}{5}=\dfrac{5+3}{5}=\boxed{\frac{8}{5}}\\\\\\4\dfrac{1}{10}=\dfrac{4\cdot10+1}{10}=\dfrac{40+1}{10}=\boxed{\frac{41}{10}}\\\\\\3\dfrac{2}{3}=\dfrac{3\cdot3+2}{3}=\dfrac{9+2}{3}=\boxed{\frac{11}{3}}\\\\\\10\dfrac{5}{9}=\dfrac{10\cdot9+5}{9}=\dfrac{90+5}{9}=\boxed{\frac{95}{9}}\\\\\\5\dfrac{4}{7}=\dfrac{5\cdot7+4}{7}=\dfrac{35+4}{7}=\boxed{\frac{39}{7}}[/tex]
