Odpowiedź:
x = [tex]\frac{-3\sqrt{2} }{2}[/tex]
Szczegółowe wyjaśnienie:
3x²+9=x²-6√2x
3x² - x² + 6√2x + 9= 0
2 x² + 6√2x + 9= 0
a = 2 , b = 6√2 , c = 9
Δ = [tex]b^{2} -4ac[/tex] = [tex](6\sqrt{2})^{2}[/tex] - 4 *2*9 = 72 - 72 = 0
x = [tex]\frac{-b}{2a}[/tex] = [tex]\frac{-6\sqrt{2} }{2*2}[/tex] = [tex]\frac{-6\sqrt{2} }{4}[/tex] = [tex]\frac{-3\sqrt{2} }{2}[/tex]
