Zadanie 1
[tex]2\dfrac{3}{5}:0,25+\dfrac{1}{8}:0,125=\dfrac{2\cdot5+3}{5}:\dfrac{25}{100}+\dfrac{1}{8}:\dfrac{125}{1000}=\\\\\\=\dfrac{13}{5}:\dfrac{1}{4}+\dfrac{1}{8}:\dfrac{1}{8}=\dfrac{13}{5}\cdot\dfrac{4}{1}+\dfrac{1}{8}\cdot\dfrac{8}{1}=\dfrac{13\cdot4}{5\cdot1}+\dfrac{1\cdot8}{8\cdot1}=\\\\\\=\dfrac{52}{5}+\dfrac{8}{8}=\dfrac{5\cdot10+2}{5}+1=10\dfrac{2}{5}+1=11\dfrac{2}{5}=11\dfrac{4}{10}=\boxed{11,4}[/tex]
Zadanie 2
[tex]2\dfrac{3}{5}:\Big(0,25+\dfrac{1}{8}:0,125\Big)=\dfrac{13}{5}:(0,25+1)=\dfrac{13}{5}:1,25=\\\\\\=\dfrac{13}{5}:\dfrac{125}{100}=\dfrac{13}{5}:\dfrac{5}{4}=\dfrac{13}{5}\cdot\dfrac{4}{5}=\dfrac{13\cdot4}{5\cdot5}=\dfrac{52}{25}=2\dfrac{2}{25}=2\dfrac{8}{100}=\boxed{2,08}[/tex]
Najpierw wykonujemy działanie w nawiasie, następnie mnożenie/dzielenie, a na koniec dodawanie/odejmowanie.
