Odpowiedź:
[tex]a = 2 \times {3}^{2} \\ a = 2 \times 9 \\ a = 18[/tex]
[tex]b = \sqrt{25 + 144} \\ b = \sqrt{169} \\ b = 13[/tex]
[tex] c = \sqrt[3]{ {2}^{6} } \\ c = {2}^{2} \\ c = 4[/tex]
[tex]d = ( \frac{1}{7} ) ^{0} \\ d = 1[/tex]
[tex]e = {5}^{5} \times ( \frac{1}{10} )^{2} \\ e = 3125 \times \frac{1}{100} \\ e = \frac{3125}{100} \\ e = \frac{125}{4} \\ e = 31 \frac{1}{4} [/tex]
[tex]e > a > b > c > d[/tex]
Odpowiedź poprawna to D
