Odpowiedź:
[tex]Zad.1\\\\4\cdot(-5)+11-16+(-7)-6\cdot(-2)-8-4+10:(-5)=-20+11-16-7+12-12-2=\\\\=-57+23=-34\\\\\\Zad.2\\\\(x-3)^2+(2-x)(2+x)=(2x+1)^2-4x^2\\\\x^2-6x+9+(2^2-x^2)=4x^2+4x+1-4x^2\\\\x^2-6x+9+4-x^2=4x+1\\\\-6x+13=4x+1\\\\-6x-4x=1-13\\\\-10x=-12\ \ |:(-10)\\\\x=\frac{12}{10}\\\\x=\frac{6}{5}\\\\x=1\frac{1}{5}[/tex]
[tex](a-b)^2=a^2-2ab+b^2\\\\(a+b)^2=a^2+2ab+b^2\\\\(a-b)(a+b)=a^2-b^2[/tex]
