Odpowiedź:
[tex]a)\ \ (125^3\cdot5^{-4}):(25^2\cdot0,2^{-3})=[(5^3)^3\cdot5^{-4}]:[(5^2)^2\cdot(\frac{1}{5})^{-3}]=\\\\=(5^9\cdot5^{-4}):(5^4\cdot5^3)=5^{9+(-4)}:5^{4+3}=5^{9-4}:5^7=5^{5}:5^{7}=5^{5-7}=5^{-2}=\\\\=(\frac{1}{5})^2=\frac{1}{25}[/tex]
[tex]b)\ \ (1-2\sqrt{2})^2(9+4\sqrt{2})=(1^2-2\cdot1\cdot2\sqrt{2}+(2\sqrt{2})^2)(9+4\sqrt{2})=\\\\=(1-4\sqrt{2}+4\cdot2)(9+4\sqrt{2})=(1-4\sqrt{2}+8)(9+4\sqrt{2})=(9-4\sqrt{2})(9+4\sqrt{2})=\\\\=9^2-(4\sqrt{2})^2=81-16\cdot2=81-32=49[/tex]
