Cześć!
Obliczenia
[tex]x=(3\frac{1}{4}-1,5)\cdot(-2\frac{1}{8}+\frac{1}{4})=(3\frac{1\cdot25}{4\cdot25}-1,5)\cdot(-\frac{17}{8}+\frac{1\cdot2}{4\cdot2})=\\\\=(3\frac{25}{100}-1,5)\cdot(-\frac{17}{8}+\frac{2}{8})=(3,25-1,5)\cdot(-\frac{15}{8})=\\\\=1,75\cdot(-\frac{15}{8})=1\frac{75}{100}\cdot(-\frac{15}{8})=1\frac{3}{4}\cdot(-\frac{15}{8})=\frac{7}{4}\cdot(-\frac{15}{8})=-\frac{105}{32}=-3\frac{9}{32}[/tex]
Liczba przeciwna do x to -x, zatem
[tex]-(-3\frac{9}{32})=3\frac{9}{32}[/tex]
Czyli końcowy wynik to 3 ⁹/₃₂
