Odpowiedź:
[tex]a)\\\\\sqrt{3}(x+\sqrt{3})=-3\\\\\sqrt{3}x+3=-3\\\\\sqrt{3}x=-3-3\\\\\sqrt{3}x=-6\ \ |:\sqrt{3}\\\\x=-\frac{6}{\sqrt{3}}\\\\x=-\frac{6}{\sqrt{3}}\cdot\frac{\sqrt{3}}{\sqrt{3}}\\\\x=-\frac{\not6^2\sqrt{3}}{\not3_{1}}\\\\x=-2\sqrt{3}\\\\\\b)\\\\x\sqrt{8}+\sqrt{2}=\sqrt{18}-\sqrt{2}x\\\\\sqrt{4\cdot2}x+\sqrt{2}x=\sqrt{18}-\sqrt{2}\\\\2\sqrt{2}x+\sqrt{2}x=\sqrt{9\cdot2}-\sqrt{2}\\\\3\sqrt{2}x=3\sqrt{2}-\sqrt{2}\\\\3\sqrt{2}x=2\sqrt{2}\ \ |:3\sqrt{2}\\\\x=\frac{2\sqrt{2}}{3\sqrt{2}}\\\\x=\frac{2}{3}[/tex]
[tex]c)\\\\2(\sqrt{5}x-4)=x\sqrt{80}+2\\\\2\sqrt{5}x-8=\sqrt{80}x+2\\\\2\sqrt{5}x-8=\sqrt{16\cdot5}x+2\\\\2\sqrt{5}x-8=4\sqrt{5}x+2\\\\2\sqrt{5}x-4\sqrt{5}x=2+8\\\\-2\sqrt{5}x=10\ \ |:(-2\sqrt{5})\\\\x=-\frac{\not10^5}{\not2_{1}\sqrt{5}}\\\\x=-\frac{5}{\sqrt{5}}\cdot\frac{\sqrt{5}}{\sqrt{5}}\\\\x=-\frac{\not5\sqrt{5}}{\not5}\\\\x=-\sqrt{5}[/tex]
[tex]e)\\\\\sqrt{2}(x+5)+2x=2(x-\sqrt{18})\\\\\sqrt{2}x+5\sqrt{2}+2x=2x-2\sqrt{18}\\\\\sqrt{2}x+5\sqrt{2}+2x=2x-2\sqrt{9\cdot2}\\\\\sqrt{2}x+5\sqrt{2}+2x=2x-2\cdot3\sqrt{2}\\\\\sqrt{2}x+5\sqrt{2}+2x=2x-6\sqrt{2}\\\\\sqrt{2}x+2x-2x=-6\sqrt{2}-5\sqrt{2}\\\\\sqrt{2}x=-11\sqrt{2}\ \ |:\sqrt{2}\\\\x=-\frac{11\sqrt{\not2}}{\sqrt{\not2}}\\\\x=-11[/tex]
