Odpowiedź:
[tex]y=-(x+2)^2-1\\\\y=-(x^2+4x+4)-1\\\\y=-x^2-4x-4-1\\\\y=-x^2-4x-5\\\\a=-1\ \ ,\ \ b=-4\\\\\Delta=b^2-4ac=(-4)^2-4\cdot(-1)\cdot(-5)=16-20=-4\\\\\\p=\frac{-b}{2a}=\frac{-(-4)}{2\cdot(-1)}=\frac{4}{-2}=-2\\\\q=\frac{-\Delta}{4a}=\frac{-(-4)}{4\cdot(-1)}=\frac{4}{-4}=-1\\\\W(-2,1)[/tex]
