Odpowiedź:
zad 3
[tex]8 = {2}^{3} \\ 4 = {2}^{2} \\ 27 = {3}^{3} \\ {8}^{2} = {( {2}^{3}) }^{2} = {2}^{6} \\ {4}^{2} = {( {2}^{2}) }^{2} = {2}^{4} \\ {27}^{4} = {( {3}^{3} )}^{4} = {3}^{12} \\ [/tex]
zad 4
a)
[tex] {27}^{5} = {( {3}^{3}) }^{5} = {3}^{15} [/tex]
b)
[tex] {81}^{3} = {( {3}^{4} )}^{3} = {3}^{12} [/tex]
