Cześć!
Obliczenia
[tex]2\sqrt{49}-6\sqrt7+3\sqrt7-\sqrt{28}=2\sqrt{7^2}-6\sqrt7+3\sqrt7-\sqrt{4\cdot7}=\\\\=2\cdot7-3\sqrt7-2\sqrt7=\boxed{14-5\sqrt7}[/tex]
[tex]2\sqrt{49} - 6\sqrt{7} + 3\sqrt{7} - \sqrt{28} = 2*7 - 6\sqrt{7} + 3\sqrt{7} - 2\sqrt{7} = 14 - \sqrt{7} + 3\sqrt{7} - 2\sqrt{7} = 14 - 5\sqrt{7}[/tex]
