Rozwiązane

2(3x+2)−3(5x−6)+4(7x+8)=111
x=
(x−7)(x+3)−2(x+1)(x−4)=−(x−1)(x+3)
x=



Odpowiedź :

1.

6x + 4 - 15x + 18 + 28x + 32 = 111

19x = 57 /:(19)

x = 3

2.

x^2 + 3x - 7x - 21 - 2(x^2 - 4x + x - 4) = -(x^2 + 3x - x - 3)

x^2 - 4x - 21 - 2x^2 + 6x + 8 = -x^2 - 2x + 3

4x = 16 /:(4)

x = 4