[tex](30t-10):5=5(6t-2):5=6t-2\\-\frac{6,3a+9}3=-\frac{3(2,1a+3)}3=-(2,1a+3)=-2,1a-3\\-6*\frac{y-9}{-2}=3(y-9)=3y-27\\\frac{x+15}{-20}*4=\frac{x+15}{-5}=\frac{-5(-\frac15x-3)}{-5}=-\frac15x-3[/tex]
Odpowiedź:
[tex](30t-10):5=30t:5-10:5=6t-2\\\\\\-\frac{6,3a+9}{3}=-\frac{6,3a}{3}-\frac{9}{3}=-2,1a-3\\\\\\-\not6^3\cdot\frac{y-9}{-\not2_{1}}=3(y-9)=3y-27\\\\\\\frac{x+15}{-\not20_{5} }\cdot\not4^1=\frac{x+15}{-5}=\frac{x}{-5}+\frac{15}{-5}=-\frac{1}{5}x-3[/tex]
