169 = 25 + [tex]h^{2}[/tex]
h = 12
Pt = [tex]\frac{ah}{2}[/tex] = 5*6 = 30 [tex]cm^{2}[/tex]
Pb1 = 20 * 12 = 240 [tex]cm^{2}[/tex]
Pb2 = 20 * 13 = 260 [tex]cm^{2}[/tex]
Pp = 5* 20 = 100 [tex]cm^{2}[/tex]
Ppowierzchni całkowitej = 30 + 30 + 240 + 260 + 100 = 660 [tex]cm^{2}[/tex]
V = Pp * H
jako Pp w V posłuży nam pole trójkąta (obracamy bryłę, H = 20cm)
V = Pt * H
V = 30[tex]cm^{2}[/tex] * 20cm
V = 600[tex]cm^{3}[/tex]
