Odpowiedź:
[tex]log_{3}\frac{3}{2} + log_{3}\frac{2}{9} = log_{3}\frac{3 * 2}{2 * 9} = log_{3}\frac{6}{18} \\= log_{3}\frac{1}{3}\\log_{3}\frac{1}{3} = x\\3^x = \frac{1}{3}\\3^x = 3^{-1}\\x = -1\\log_{3}\frac{1}{3} = -1[/tex]
