Odpowiedź:
[tex] {(2 - x)}^{3} \times {( \sqrt{2}x - 1) }^{3} = \\ ( {2}^{3} - 3 \times 2 \times {x}^{2} + 3 \times {2}^{2} \times x - {x}^{3} ) \times ( {( \sqrt{2}x) }^{3} - 3 \times ( \sqrt{2} x {)}^{2} \times 1 + 3 \times \sqrt{2} x \times 1 - 1) = \\ (8 - 6 {x}^{2} + 12x - {x}^{3} ) \times (2 \sqrt{2} {x}^{3} - 6 {x}^{2} + 3 \sqrt{2} x - 1) = \\ 16 \sqrt{2} {x}^{3} - 48 {x}^{2} + 24 \sqrt{2} x - 8 - 12 \sqrt{2 }{x}^{5} + 36 {x}^{4} - 18 \sqrt{2} {x}^{3} + 6 {x}^{2} + 24 \sqrt{2} {x}^{5} - 72 {x}^{3} + 36 \sqrt{2} {x}^{2} - 12x - 2 \sqrt{2} {x}^{6} + 6 {x}^{5} - 3 \sqrt{2} {x}^{4} + {x}^{3} = \\ [/tex]
najwyższa potęga to 6
więc wzpółczynnik przy najwyższej potędze to
[tex] - 2 \sqrt{2} [/tex]
Odp B
