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Obliczenia
[tex]3^{-3}\cdot(\frac{1}{9})^{-3}=(3\cdot\frac{1}{9})^{-3}=(\frac{1}{3})^{-3}=3^3=\boxed{27}\\\\4^{-2}\cdot(\frac{1}{16})^{-2}=(4\cdot\frac{1}{16})^{-2}=(\frac{1}{4})^{-2}=4^2=\boxed{16}\\\\5^{-1}\cdot(\frac{1}{125})^{-1}=(5\cdot\frac{1}{125})^{-1}=(\frac{1}{25})^{-1}=\boxed{25}\\\\6^{-2}\cdot(\frac{1}{36})^{-2}=(6\cdot\frac{1}{36})^{-2}=(\frac{1}{6})^{-2}=6^2=\boxed{36}[/tex]
Wykorzystane wzory
[tex]a^m\cdot b^m=(a\cdot b)^m\\\\a^{-n}=\frac{1}{a^n}[/tex]
