Odpowiedź:
d = a[tex]\sqrt{2}[/tex] = 6
a = 6 j
sin 30 ° = 6/b2 = 1/2 /*b2
6 = 1/2b2 /*2
b2 = 12 j
12^2 = b^2 + 6^2
144 = 36 + b^2
b^2 = 144 - 36 = 108
b = [tex]\sqrt{108}[/tex] = 6[tex]\sqrt{3}[/tex] j
Obwód = 3 * 6 + 12 + 6[tex]\sqrt{3}[/tex] = 18 + 12 + 6[tex]\sqrt{3}[/tex] = 30 + 6[tex]\sqrt{3}[/tex] j
