a) [tex]x+\frac{1}{3}+2=x+\frac{2}{2}\\\\x+2\frac{1}{3}=x+1\\\\x-x=1-2\frac{1}{3}\\\\\boxed{0\neq-1\frac{1}{3}}[/tex]
Równanie sprzeczne.
b) [tex]x+\frac{2}{2}-3=x+\frac{1}{2}\\\\x+1-3=x+\frac{1}{2}\\\\x-2=x+\frac{1}{2}\\\\x-x=\frac{1}{2}+2\\\\\boxed{0\neq2\frac{1}{2}}[/tex]
Równanie sprzeczne.
c) [tex]x+\frac{2}{2}-1=2x+\frac{4}{3}\\\\x+\not1-\not1=2x+1\frac{1}{3}\\\\x-2x=1\frac{1}{3}\\\\-x=1\frac{1}{3}\,|\cdot(-1)\\\\\boxed{x=-1\frac{1}{3}}[/tex]
d) [tex]6x-\frac{5}{12}=2x-\frac{3}{4}\\\\6x-2x=-\frac{3\cdot3}{4\cdot3}+\frac{5}{12}\\\\4x=-\frac{9}{12}+\frac{5}{12}\\\\4x=-\frac{4}{12}\,|\div4\\\\\boxed{x=-\frac{1}{12}}[/tex]
