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[tex]\sqrt{16}+\sqrt9-\sqrt{16+9}=\sqrt{4^2}+\sqrt{3^2}-\sqrt{25}=4+3-\sqrt{5^2}=7-5=\boxed2\\\\\sqrt{36+64}=\sqrt{100}=\sqrt{10^2}=\boxed{10}\\\\4\sqrt[3]{-8}-\sqrt{64}=4\sqrt[3]{(-2)^3}-\sqrt{8^2}=4\cdot(-2)-8=-8-8=\boxed{-16}\\\\\sqrt[3]{9^2-17}-\sqrt{4^3}=\sqrt[3]{81-17}+\sqrt{64}=\sqrt[3]{64}+\sqrt{8^2}=\sqrt[3]{4^3}+8=4+8=\boxed{12}[/tex]
