1.
[tex]a) \ \frac{2}{3}+\frac{1}{3} =\frac{3}{3} = 1\\\\b) \ 3\frac{5}{8}+\frac{7}{8} = 3\frac{12}{8} = 4\frac{4}{8} = 4\frac{1}{2}\\\\c) \ 4\frac{2}{5}+3\frac{4}{5} = 7\frac{6}{5} = 8\frac{1}{5}\\\\d) \ 6\frac{2}{5}+3\frac{1}{5}+2\frac{4}{5} = 11\frac{7}{5} = 12\frac{2}{5}[/tex]
2.
[tex]a) \ 4\frac{5}{6}-\frac{4}{6}=4\frac{1}{6}\\\\b) \ 5\frac{5}{6}-4 = 1\frac{5}{6}\\\\c) \ 5-\frac{2}{5} = 4\frac{5}{5}-\frac{2}{5} = 4\frac{3}{5}\\\\d) \ 5\frac{1}{6}-2\frac{5}{6} = 4\frac{7}{6}-2\frac{5}{6} = 2\frac{2}{6} = 2\frac{1}{3}[/tex]
