Rozwiązanie:
[tex]$ \lim_{n \to \infty} \Big(\frac{2n+3}{2n+1} \Big)^{7n+4}= \lim_{n \to \infty} \Big[\Big(1+\frac{2}{2n+1} \Big)^{\frac{2n+1}{2} }\Big]^{\frac{2(7n+4)}{2n+1} }= \lim_{n \to \infty} e^{\frac{14n+8}{2n+1} }=e^{7}[/tex]
