Odpowiedź :
Odpowiedź:
tg300° = tg(360° - 60°) = - tg60° = - √3
cos225° = cos(270° - 45°) = - sin45° = - √2/2
[tex]tg300^{o} = tg(360^{o}-60^{o}) = -tg60^{o} = -\sqrt{3}\\\\cos225^{o} = cos(180^{o}+45^{o}) = -cos45^{o}=-\frac{\sqrt{2}}{2}[/tex]
Odpowiedź:
tg300° = tg(360° - 60°) = - tg60° = - √3
cos225° = cos(270° - 45°) = - sin45° = - √2/2
[tex]tg300^{o} = tg(360^{o}-60^{o}) = -tg60^{o} = -\sqrt{3}\\\\cos225^{o} = cos(180^{o}+45^{o}) = -cos45^{o}=-\frac{\sqrt{2}}{2}[/tex]