Odpowiedź :
[tex]\sqrt{\frac{9}{25}}\cdot\sqrt{\frac{25}{36}} + (\sqrt{361})^{2}-4\cdot\sqrt{0,49}\cdot\sqrt{100} =\\\\=\frac{\sqrt{9}}{\sqrt{25}}\cdot\frac{\sqrt{25}}{\sqrt{36}}+361 - 4\cdot\sqrt{0,7^{2}}\cdot\sqrt{10^{2}}\\\\=\frac{3}{5}\cdot\frac{5}{6} + 361 - 4\cdot0,7\cdot10=\\\\0,5+361-28=\\\\=361,5 - 28=333,5[/tex]