a) trójkąt w lewym górnym rogu
[tex] {2}^{2} + {4}^{2} = a {}^{2} [/tex]
[tex]4 + 16 = {a}^{2} [/tex]
[tex]20 = {a }^{2} \\ \sqrt{20 } = a[/tex]
trójkąt u góry po środku
[tex] {3 \sqrt{5} }^{2} - {2 \sqrt{5}}^{2} = {l}^{2} [/tex]
b)
trójkąt w lewym dolnym rogu
[tex] {6}^{2} + {3}^{2} = {c}^{2} [/tex]
[tex]36 + 9 = {c}^{2} [/tex]
[tex]45 = {c}^{2} [/tex]
[tex] \sqrt{45} = c[/tex]
[tex] { \sqrt{45} }^{2} + {2}^{2} = {x}^{2} [/tex]
[tex]45 + 4 = {x}^{2} \\ 49 = {x }^{2} \\ \sqrt{49} = x[/tex]
