Odpowiedź:
[tex]\sqrt{252} =[/tex] [tex]\sqrt{2 * 2 * 3 * 3* 7 } =[/tex] 6 [tex]\sqrt{7}[/tex]
·[tex]\sqrt{108} = \sqrt{ 2 * 54} = \sqrt{2 * 9 * 6} = \sqrt{2 * 2 *9 *3} = 6 \sqrt{3}[/tex]
[tex]\sqrt{32} - \sqrt{50} = \sqrt{4* 8} - \sqrt{25 *2} = \sqrt{4*4*2} -\sqrt{25*2} = 4\sqrt{2} - 5\sqrt{2} = - \sqrt{2}[/tex]
[tex]\sqrt[3]{432} - \sqrt[3]{250} = \sqrt[3]{2*2*108} - \sqrt[3]{25*10} = \sqrt[3]{2*2*2*54} - \sqrt[3]{5*5*5*2} = \sqrt[3]{2*2*2 * 27*2} - \sqrt[3]{x} = 6\sqrt[3]{2} - 5\sqrt[3]{2} = \sqrt[3]{2}[/tex]
[tex]\sqrt[3]{2\frac{10}{27}} = \sqrt[3]{\frac{54 + 10}{27}} = \sqrt[3]{\frac{64}{27}} = \frac{\sqrt[3]{64} }{\sqrt[3]{27} } = \frac{4}{3}[/tex]
[tex]\sqrt{32} *\sqrt{8} = \sqrt{32 * 8} = \sqrt{4 * 8*8} = 8 *2 = 16[/tex]
[tex]\frac{\sqrt{54} *\sqrt{350} }{\sqrt{21} } = \sqrt{\frac{54*350}{21} } = \sqrt{\frac{(9*2*3) *(5*7*10)}{3*7} } = \sqrt{9*2*5*2*5} = 3*2*5= 30[/tex]
Wykonaj mnożenie:
4x - (x+1)(2x-1) = [tex]4x - (2x^{2} -x +2x-1) = 4x -2x^{2} +x-2x+1 = -2x^{2} +3x +1[/tex]
Liczę na naj :)
