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Górny rząd
[tex](\frac{2}{5})^2=\frac{2^2}{5^2}=\frac{2\cdot2}{5\cdot5}=\frac{4}{25}\\\\(1\frac{2}{3})^3=(\frac{1\cdot3+2}{3})^3=(\frac{3+2}{3})^3=(\frac{5}{3})^3=\frac{5^3}{3^3}=\frac{5\cdot5\cdot5}{3\cdot3\cdot3}=\frac{125}{27}=4\frac{17}{27}\\\\(\frac{4}{11})^2=\frac{4^2}{11^2}=\frac{4\cdot4}{11\cdot11}=\frac{16}{121}[/tex]
Drugi rząd
[tex](\frac{3}{4})^3=\frac{3^3}{4^3}=\frac{3\cdot3\cdot3}{4\cdot4\cdot4}=\frac{27}{64}\\\\(3\frac{1}{2})^3=(\frac{3\cdot2+1}{2})^3=(\frac{6+1}{2})^3=(\frac{7}{2})^3=\frac{7^3}{2^3}=\frac{7\cdot7\cdot7}{2\cdot2\cdot2}=\frac{343}{8}=42\frac{7}{8}\\\\(3\frac{4}{11})^2=(\frac{3\cdot11+4}{11})^2=(\frac{33+4}{11})^2=(\frac{37}{11})^2=\frac{37^2}{11^2}=\frac{37\cdot37}{11\cdot11}=\frac{1369}{121}=11\frac{38}{121}[/tex]
