Odpowiedź:
[tex]8^{2} +4^{2} =d^{2} \\64 + 16 = d^{2} \\d = \sqrt{80} = \sqrt{16 } *\sqrt{5} =4\sqrt{5}[/tex]
[tex]sin \alpha =\frac{4}{4\sqrt{5} } =\frac{\sqrt{5} }{5}[/tex]
[tex]cos \alpha =\frac{8}{4\sqrt{5} } =\frac{2\sqrt{5} }{5}[/tex]
[tex]tg \alpha = \frac{4}{8} =\frac{1}{2} \\\\ctg \alpha = \frac{8}{4} =2[/tex]
[tex]sin \beta = cos \alpha =\frac{2\sqrt{5} }{5}[/tex]
[tex]cos\beta =sin\alpha = \frac{\sqrt{5} }{5}[/tex]
[tex]tg \beta = ctg \alpha =2[/tex]
[tex]ctg \beta = tg\alpha = \frac{1}{2}[/tex]
Szczegółowe wyjaśnienie:
