Odpowiedź :
Odpowiedź:
Ix + 2I = 1/3x + 2
x + 2 = 1/3x + 2 ∨ x + 2 = - (1/3x + 2) = - 1/3x - 2
x - 1/3x = 2 - 2 ∨ x + 1/3x = - 2 - 2
2/3x = 0 ∨ 1 1/3x = - 4
x = 0 ∨ 4/3x = - 4
x = 0 ∨ x = - 4 : 4/3
x = 0 ∨ x = - 4 * 3/4
x = 0 ∨ x = - 3
|x + 2| = x/3 + 2
x + 2 = x/3 + 2 \/ x + 2 = -x/3 - 2
2x/3 = 0 \/ 4x/3 = -4
x = 0 \/ 4x = -12
x = 0 \/ x = -3
x + 2 = x/3 + 2 \/ x + 2 = -x/3 - 2
2x/3 = 0 \/ 4x/3 = -4
x = 0 \/ 4x = -12
x = 0 \/ x = -3