Odpowiedź:
[tex] {a}^{2} + {15}^{2} = {17}^{2} \\ {a}^{2} + 225 = 289 \\ {a}^{2} = 289 - 225 \\ {a}^{2} = 64 \\ a = \sqrt{64} \\ a = 8[/tex]
[tex]( {4 \sqrt{10} })^{2} + {3}^{2} = {b}^{2} \\ 160 + 9 = {b}^{2} \\ {b}^{2} = 169 \\ b = \sqrt{169} \\ b = 13[/tex]
