[tex]Dane:\\m = 40 \ kg\\r = 200 \ cm = 2 \ m\\T = 1 \ min = 60 \ s\\Szukane:\\F_{d} = ?\\\\\\F_{d} = \frac{4\pi^{2} mr}{T^{2}}\\\\F_{d} = \frac{4\cdot3,14^{2}\cdot40 \ kg\cdot2 \ m}{(60 \ s)^{2}} = \frac{78,8768 \ kg\cdot m}{3600 \ s^{2}}\\\\\boxed{F_{d}\approx0,022 \ N\approx22 \ mN}[/tex]
