Odpowiedź:
[tex] {9}^{2} + {a}^{2} = {15}^{2} \\ 81 + {a}^{2} = 225 \\ {a}^{2} = 225 - 81 \\ {a}^{2} = 144 \\ a = \sqrt{144} \\ a = 12[/tex]
[tex] { \sqrt{7} }^{2} + {(2 \sqrt{5)} }^{2} = {b }^{2} \\ 7 + 20 = {b}^{2} \\ 27 = {b}^{2} \\ b = \sqrt{27} \\ b = 3 \sqrt{3} [/tex]
