[tex]2\dfrac{1}{7}\cdot1\dfrac{7}{15}=\dfrac{7\cdot2+1}{7}\cdot\dfrac{15\cdot1+7}{15}=\dfrac{\not\!\!15}{7}\cdot\dfrac{22}{\not\!\!15}=\dfrac{22}{7}=\boxed{3\dfrac{1}{7}}[/tex]
