Odpowiedź:
[tex]c)\ \ \ \ \dfrac{0,4}{9,8+(-7\frac{4}{5})}=\dfrac{0,4}{9,8-7\frac{4}{5}}=\dfrac{0,4}{9,8-7,8}=\dfrac{0,4}{2}=0,2\\\\\\d)\ \ \ \ \dfrac{\frac{3}{8}+2\frac{2}{5}}{0,05}-(5^2-3^2)=\dfrac{\frac{15}{40}+2\frac{16}{40}}{\frac{5}{100}}-(25-9)=\dfrac{2\frac{31}{40}}{\frac{1}{20}}-16=2\frac{31}{40}:\frac{1}{20}-16=[/tex]
[tex]=\frac{111}{\not40_{2}}\cdot\not20^1-16=\frac{111}{2}-16=55\frac{1}{2}-16=39\frac{1}{2}[/tex]
