Odpowiedź :
Cześć!
Obliczenia
[tex]4\sqrt3+\sqrt{75}-\sqrt{48}=4\sqrt3+\sqrt{25\cdot3}-\sqrt{16\cdot3}=\\\\=4\sqrt3+\sqrt{5^2\cdot3}-\sqrt{4^2\cdot3}=4\sqrt3+5\sqrt3-4\sqrt3=9\sqrt3-4\sqrt3=\boxed{5\sqrt3}[/tex]
Cześć!
Obliczenia
[tex]4\sqrt3+\sqrt{75}-\sqrt{48}=4\sqrt3+\sqrt{25\cdot3}-\sqrt{16\cdot3}=\\\\=4\sqrt3+\sqrt{5^2\cdot3}-\sqrt{4^2\cdot3}=4\sqrt3+5\sqrt3-4\sqrt3=9\sqrt3-4\sqrt3=\boxed{5\sqrt3}[/tex]