Odpowiedź:
Szczegółowe wyjaśnienie:
[tex](\sqrt[3]{\frac{64}{27} } -\sqrt[3]{\frac{125}{216} } ):\sqrt[3]{\frac{125}{64} } *\sqrt[3]{\frac{27}{8} } +\sqrt[3]{\frac{8}{125} } =(\frac{4}{3} -\frac{5}{6} ):\frac{5}{4} *\frac{3}{2} +\frac{2}{5} =\\(\frac{8}{6} -\frac{5}{6}):\frac{5}{4} *\frac{3}{2} +\frac{2}{5} =\frac{3}{6} :\frac{5}{4} *\frac{3}{2} +\frac{2}{5} =\frac{3}{6}*\frac{4}{5} *\frac{3}{2} +\frac{2}{5} =\frac{3}{5} +\frac{2}{5} =1[/tex]
Zad.2
a.
[tex]\sqrt[3]{x}=-6\\x=(-6)^3\\x=-216\\[/tex]
b.
[tex]\sqrt[3]{x+40}=3\\x+40=3^3\\x=27-40\\x=-13[/tex]
c.
[tex]\sqrt[3]{3x} =3\\3x=3^3\\3x=27\\x=9[/tex]
