26/72 porównaj liczby a) x=81^20 i y=1024^8 b) x=128^36 i y=4^125 c) x= ( 1/27)^-48 i y= 243^28 d) x=(2√2)^28 i y=(√8/64) ^-6

Odpowiedź:
a) x = 81²⁰ = (3⁴)²⁰ = 3⁸⁰
y = 1024⁸ = (2¹⁰)⁸ = 2⁸⁰
x > y
b) x = 128³⁶ = (2⁷)³⁶ = 2²⁵²
y = 4¹²⁵ = (2²)¹²⁵ = 2²⁵⁰
x > y
c) [tex]x = (\frac{1}{27})^{-27}[/tex] = (3⁻¹)⁻²⁷ = 3²⁷
y = 243²⁸ = (3⁵)²⁸ = 3¹⁴⁰
x < y
d) [tex]x = (2\sqrt{2})^{28} = (2*2^{\frac{1}{2})^{28} = 2^{42}[/tex]
[tex]y = (\frac{\sqrt{8}}{64})^{-6} = (\frac{2^{\frac{3}{2}}}{2^{6}})^{-6}=(2^{-\frac{9}{2}})^{-6}=2^{27}[/tex]
x > y