Odpowiedź:
mH2S= 2×1u+ 32u= 2u+ 32u= 34u
mCO= 12u+ 16u= 28u
mP4O10= 4×31u + 10× 16u= 124u+ 160u= 284u
mH2SO3= 2×1u+ 32u+ 3×16u= 2u+ 32u+ 48u= 82u
mAl(OH)3= 27u+ 3× 16u+ 3× 1u= 27u+ 48u+ 3u= 78u
m(NH4)2CrO4= 2+ 14u+ 8×1u+ 52u+ 4×16u= 28u+ 8u+ 52u+ 64u= 154u
Wyjaśnienie: