Odpowiedź:
[tex]\dfrac{2}{6\sqrt{5}}=\dfrac{2}{6\sqrt{5}}\cdot\dfrac{\sqrt{5}}{\sqrt{5}}=\dfrac{2\sqrt{5} }{6\cdot5}=\dfrac{\not2^1\sqrt{5}}{\not30_{15}}=\dfrac{\sqrt{5}}{15}[/tex]
