Odpowiedź:
Szczegółowe wyjaśnienie:
Zadanie 1
a)2-[tex]\frac{2}{3} =1\frac{3}{3} -\frac{2}{3} =1\frac{1}{3}[/tex]
b)[tex]-2\frac{1}{4} + 3\frac{1}{3} = -2\frac{3}{12} + 3\frac{4}{12} = 1\frac{1}{12}[/tex]
c)[tex]3\frac{1}{4} : (0,5 - \frac{3}{8}) = 3\frac{1}{4} : (\frac{5}{10} - \frac{3}{8})=3\frac{1}{4} : (\frac{1}{2} - \frac{3}{8})=3\frac{1}{4} : (\frac{4}{8} - \frac{3}{8})=3\frac{1}{4} : \frac{1}{8} =\\\frac{13}{4} : \frac{1}{8}=\frac{13}{4} * \frac{8}{1}=\frac{104}{4}= 26\\[/tex]
d)[tex]\frac{(-\frac{1}{3}) ^{2}*3+0,2:\frac{3}{4} }{-2} =\frac{(\frac{1}{9}) *3+0,2:\frac{3}{4} }{-2}=\frac{(\frac{1}{9}) *3+0,2:\frac{3}{4} }{-2} = \frac{(\frac{3}{9}) +\frac{1}{2} :\frac{3}{4} }{-2}=\frac{(\frac{3}{9}) +\frac{1}{2} *\frac{4}{3} }{-2}=\frac{(\frac{3}{9}) +\frac{4}{6} }{-2}=\frac{(\frac{3}{9}) +\frac{4}{6} }{-2}=\frac{(\frac{6}{18}) +\frac{12}{18} }{-2}=-\frac{1}{2}[/tex]
Zadanie 2
a)-5,35 *(-6)=32,1
b)[tex](2,3)^{2} =2,3*2,3= 5,29[/tex]
c)[tex]-0,6*(-\frac{1}{3} )^{2} =-0,6*\frac{1}{9} =-\frac{6}{10} *\frac{1}{9}=-\frac{3}{5} *\frac{1}{9}=-\frac{1}{5} *\frac{1}{3}=-\frac{1}{15}[/tex]
d)-4,8:(0,8)=6
Zadanie 3
a)[tex]5,65-(-1\frac{1}{3} )=5,65+(1\frac{1}{3} )=5,65+1,(3)=6,98(3)[/tex]
b)[tex]-4\frac{3}{4} -2,2=-4\frac{3}{4} -2\frac{2}{10}= -4\frac{3}{4} -2\frac{1}{5}=-4\frac{15}{20} -2\frac{4}{20}=-6\frac{19}{20}[/tex]
c)[tex]-5\frac{5}{7} + 2,6=-5\frac{5}{7} + 2\frac{3}{5} =-5\frac{25}{35} + 2\frac{21}{35}=-3\frac{4}{35}[/tex]
d)[tex]-4,9-(-2\frac{7}{8})= -4\frac{9}{10} +(2\frac{7}{8})=-4\frac{36}{40} +(2\frac{35}{40})=-2\frac{1}{40}[/tex]
