a)
Dane:
[tex]y = a[/tex]
[tex]x = 2a[/tex]
[tex]5 = a \sqrt{3} [/tex]
Zatem
[tex]a \sqrt{3} = 5 | \div \sqrt{3} \\ a = \frac{5}{ \sqrt{3} } = \frac{5 \sqrt{3} }{3} = 1 \frac{2}{3} \sqrt{3} [/tex]
[tex]2a = 1 \frac{2}{3} \sqrt{3} \times 2 \\ 2a = \frac{5}{3} \sqrt{3} \times \frac{2}{1} \\ 2a = \frac{10}{3} \sqrt{3} = 3 \frac{1}{3} \sqrt{3} [/tex]
Zatem
[tex]x = 3 \frac{1}{3} \sqrt{3} \\ y = 1 \frac{2}{3} \sqrt{3} [/tex]
b)
Dane:
[tex]a = 6[/tex]
[tex]y = 2a[/tex]
[tex]x = a \sqrt{2} [/tex]
Zatem
[tex]y = 6 \times 2 = 12[/tex]
[tex]a \sqrt{2} = 6 \sqrt{2} [/tex]
Zatem
[tex]x = 6 \sqrt{2} \\ y = 12[/tex]
Myślę że pomogłem ;)
